Example : 1
Let’s say you're trying to find the likelihood of rolling a 3 on a 6-sided die. “Rolling a 3” is the event, and since we know that a 6-sided die can land any one of 6 numbers, the number of outcomes is 6. So, we know that in this case, there are 6 possible events and 1 outcome whose probability we’re interested in calculating
Example : 2
What is the likelihood of choosing a day that falls on the weekend when randomly picking a day of the week? "Choosing a day that falls on the weekend" is our event, and the number of outcomes is the total number of days in a week: 7.
Example : 3
A jar contains 4 blue marbles, 5 red marbles and 11 white marbles. If a marble is drawn from the jar at random, what is the probability that this marble is red? "Choosing a red marble" is our event, and the number of outcomes is the total number of marbles in the jar, 20.
https://news.1rj.ru/str/Maths4Magic
Let’s say you're trying to find the likelihood of rolling a 3 on a 6-sided die. “Rolling a 3” is the event, and since we know that a 6-sided die can land any one of 6 numbers, the number of outcomes is 6. So, we know that in this case, there are 6 possible events and 1 outcome whose probability we’re interested in calculating
Example : 2
What is the likelihood of choosing a day that falls on the weekend when randomly picking a day of the week? "Choosing a day that falls on the weekend" is our event, and the number of outcomes is the total number of days in a week: 7.
Example : 3
A jar contains 4 blue marbles, 5 red marbles and 11 white marbles. If a marble is drawn from the jar at random, what is the probability that this marble is red? "Choosing a red marble" is our event, and the number of outcomes is the total number of marbles in the jar, 20.
https://news.1rj.ru/str/Maths4Magic
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Example : 4
🔶Add up all possible event likelihoods to make sure they equal 1 🔷
"The likelihood of all possible events needs to add up to 1 or to 100%. If the likelihood of all possible events doesn't add up to 100%, you've most likely made a mistake because you've left out a possible event. Recheck your math to make sure you’re not omitting any possible outcomes."
The likelihood of rolling a 3 on a 6-sided die is 1/6. But the probability of rolling all five other numbers on a die is also 1/6. 1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 6/6 , which = 100%
🔶Add up all possible event likelihoods to make sure they equal 1 🔷
"The likelihood of all possible events needs to add up to 1 or to 100%. If the likelihood of all possible events doesn't add up to 100%, you've most likely made a mistake because you've left out a possible event. Recheck your math to make sure you’re not omitting any possible outcomes."
The likelihood of rolling a 3 on a 6-sided die is 1/6. But the probability of rolling all five other numbers on a die is also 1/6. 1/6 + 1/6 + 1/6 + 1/6 + 1/6 + 1/6 = 6/6 , which = 100%
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Example : 5
🔶 Represent the probability of an impossible outcome with a 0. 🔷
"This just means that there is no chance of an event happening, and occurs anytime you deal with an event that simply cannot happen. While calculating a 0 probability is not likely, it’s not impossible either."
For example, if you were to calculate the probability of the Easter holiday falling on a Monday in the year 2020, the probability would be 0 because Easter is always on a Sunday.
🔶 Represent the probability of an impossible outcome with a 0. 🔷
"This just means that there is no chance of an event happening, and occurs anytime you deal with an event that simply cannot happen. While calculating a 0 probability is not likely, it’s not impossible either."
For example, if you were to calculate the probability of the Easter holiday falling on a Monday in the year 2020, the probability would be 0 because Easter is always on a Sunday.
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Example : 6
🔶 Deal with each probability separately to calculate independent events. 🔷
Once you’ve figured out what these probabilities are, you’ll calculate them separately. Say you wanted to know the probability of rolling a 5 twice consecutively on a 6-sided die. You know that the probability of rolling one five is 1/6, and the probability of rolling another five with the same die is also 1/6. The first outcome doesn’t interfere with the second.
🔶 Deal with each probability separately to calculate independent events. 🔷
Once you’ve figured out what these probabilities are, you’ll calculate them separately. Say you wanted to know the probability of rolling a 5 twice consecutively on a 6-sided die. You know that the probability of rolling one five is 1/6, and the probability of rolling another five with the same die is also 1/6. The first outcome doesn’t interfere with the second.
Example : 7
Consider the event: Two cards are drawn randomly from a deck of cards. What is the likelihood that both cards are clubs? The likelihood that the first card is a club is 13/52, or 1/4. (There are 13 clubs in every deck of cards.)
Now, the likelihood that the second card is a club is 12/51, since 1 club will have already been removed. This is because what you do the first time affects the second. If you draw a 3 of clubs and don't put it back, there will be one less club and one less card in the deck (51 instead of 52).
Consider the event: Two cards are drawn randomly from a deck of cards. What is the likelihood that both cards are clubs? The likelihood that the first card is a club is 13/52, or 1/4. (There are 13 clubs in every deck of cards.)
Now, the likelihood that the second card is a club is 12/51, since 1 club will have already been removed. This is because what you do the first time affects the second. If you draw a 3 of clubs and don't put it back, there will be one less club and one less card in the deck (51 instead of 52).
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Example : 8
A jar contains 4 blue marbles, 5 red marbles, and 11 white marbles. If 3 marbles are drawn from the jar at random, what is the probability that the first marble is red, the second marble is blue, and the third is white?
The probability that the first marble is red is 5/20, or 1/4. The probability of the second marble being blue is 4/19, since we have 1 less marble, but not 1 less blue marble. And the probability that the third marble is white is 11/18, because we’ve already chosen 2 marbles.
A jar contains 4 blue marbles, 5 red marbles, and 11 white marbles. If 3 marbles are drawn from the jar at random, what is the probability that the first marble is red, the second marble is blue, and the third is white?
The probability that the first marble is red is 5/20, or 1/4. The probability of the second marble being blue is 4/19, since we have 1 less marble, but not 1 less blue marble. And the probability that the third marble is white is 11/18, because we’ve already chosen 2 marbles.
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