Forwarded from Eunuch
Report on my Interview
Literally when I started my PC stacked🤯 and he was a peace guy he literally gave me 20 min after that I changed my PC with my friend and shared that.
1. After I shared my PC he introduced himself to me and also told me to share my screen asked me to go from tab desktop to check whether I shared my screen.
Also he asked me to show my ID in front of the screen.
2. He dropped the question it was
leetcode 1198 Premium question (https://github.com/doocs/leetcode/blob/main/solution/1100-1199/1198.Find%20Smallest%20Common%20Element%20in%20All%20Rows/README_EN.md)
3. I asked him to give me some time to understand the problem. When I saw the word strictly increasing I thought the question was Monotonic Stack but it wasn't.
4. After few silent minutes I think my adrelanine hormone just increased and the optimal one came to me but not the brute.
5. So I thought of a way to just sort the dictionary and make explain it as brute force. And literally it worked and asked me to Optimize it after I explained the time complexity. He also guided me on some other optimal related things like he told me to finish it inside the nested loop since it is strictly increasing matrix so I literally did that and explained as Optimal form and after I explained I implemented it quickly I started implementing while I was explaining the Brute one.
6. The technical was like that we finished it in 30min after that he gave 3 min and copy the code run and submit. He didn't told me whether it was accepted but I personally tested it on sharepad and it was correct for th given testcases.
7. After 5 min we started the Behavioural Interview he asked me 7 questions and agree on the policy the questions was literally same as the
G4 Interview Template
so I highly recommend to prepare on it.
8. After the interview I asked him about A2SV and other tech staff since he was Graduate student. And the interview entirely ended in 1:10 hr.
Forwarded from Eunuch
Today's Interview Question```
You are given a string s, which contains stars *.
In one operation, you can:
Choose a star in s.
Remove the closest non-star character to its left, as well as remove the star itself.
Return the string after all stars have been removed.
Note:
The input will be generated such that the operation is always possible.
It can be shown that the resulting string will always be unique.
Example 1:
Input: s = "leet**cod*e"
Output: "lecoe"
Explanation: Performing the removals from left to right:
- The closest character to the 1st star is 't' in "leet**cod*e". s becomes "lee*cod*e".
- The closest character to the 2nd star is 'e' in "lee*cod*e". s becomes "lecod*e".
- The closest character to the 3rd star is 'd' in "lecod*e". s becomes "lecoe".
There are no more stars, so we return "lecoe".
Example 2:
Input: s = "erase*****"
Output: ""
Explanation: The entire string is removed, so we return an empty string.
Constraints:
1 <= s.length <= 10**5
s consists of lowercase English letters and stars *.
The operation above can be performed on s.
def fun(s):
stack = []
for c in s:
if c != "*":
stack.append(c)
else:
stack.pop()
return "".join(stack)
print(fun("erase*****"))
`Forwarded from Leetcode with dani
Todays interview question
A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include letters and numbers.
Given a string s, return true if it is a palindrome, or false otherwise.
Example 1:
Input: s = "A man, a plan, a canal: Panama"
Output: true
Explanation: "amanaplanacanalpanama" is a palindrome.
Example 2:
Input: s = "race a car"
Output: false
Explanation: "raceacar" is not a palindrome.
Example 3:
Input: s = " "
Output: true
Explanation: s is an empty string "" after removing non-alphanumeric characters.
Since an empty string reads the same forward and backward, it is a palindrome.
Constraints:
1 <= s.length <= 2 * 105
s consists only of printable ASCII characters.
Forwarded from Leetcode with dani
"""
Question Denoscription
Given an input string s, reverse the order of the words.
A word is defined as a sequence of non-space characters. The words in s will be separated by at least one space.
Return a string of the words in reverse order concatenated by a single space.
Note that s may contain leading or trailing spaces or multiple spaces between two words.
The returned string should only have a single space separating the words. Do not include any extra spaces.
Example 1:
Input: s = "the sky is blue"
Output: "blue is sky the"
Example 2:
Input: s = " hello world "
Output: "world hello"
Explanation: Your reversed string should not contain leading or trailing spaces.
Example 3:
Input: s = "a good example"
Output: "example good a"
Explanation: You need to reduce multiple spaces between two words to a single space in the reversed string.
Constraints:
1 <= s.length <= 104
s contains English letters (upper-case and lower-case), digits, and spaces ' '.
There is at least one word in s.
"a good example"
["a","good","example"]
L R
[example,"good","a"]
"""
#will s will split
#variables left->0 rght ->len(splited)-1
#will have a while l<L left+=1 righ-=1
def revercing_word(s):
words=[]
for word in s.split(" "):
if word:
words.append(word)
left=0
right=len(words)-1
while left<right:
words[left],words[right]= words[right],words[left]
left+=1
right-=1
return " ".join(words)
print(revercing_word("hello world"))
Forwarded from Leetcode with dani
another interview question
You are given a 0-indexed integer array nums.
Swaps of adjacent elements are able to be performed on nums.
A valid array meets the following conditions:
The largest element (any of the largest elements if there are multiple) is at the rightmost position in the array.
The smallest element (any of the smallest elements if there are multiple) is at the leftmost position in the array.
Return the minimum swaps required to make nums a valid array.
Example 1:
Input: nums = [3,4,5,5,3,1]
Output: 6
Explanation: Perform the following swaps:
- Swap 1: Swap the 3rd and 4th elements, nums is then [3,4,5,3,5,1].
- Swap 2: Swap the 4th and 5th elements, nums is then [3,4,5,3,1,5].
- Swap 3: Swap the 3rd and 4th elements, nums is then [3,4,5,1,3,5].
- Swap 4: Swap the 2nd and 3rd elements, nums is then [3,4,1,5,3,5].
- Swap 5: Swap the 1st and 2nd elements, nums is then [3,1,4,5,3,5].
- Swap 6: Swap the 0th and 1st elements, nums is then [1,3,4,5,3,5].
It can be shown that 6 swaps is the minimum swaps required to make a valid array.
Example 2:
Input: nums = [9]
Output: 0
Explanation: The array is already valid, so we return 0.
Constraints:
1 <= nums.length <= 10^5
1 <= nums[i] <= 10^5
Forwarded from typing.......
You are given a 0-indexed string s consisting of only lowercase English letters, and an integer count. A substring of s is said to be an equal count substring if, for each unique letter in the substring, it appears exactly count times in the substring.
Return the number of equal count substrings in s.
A substring is a contiguous non-empty sequence of characters within a string.
Example 1:
Input: s = "aaabcbbcc", count = 3
Output: 3
Explanation:
The substring that starts at index 0 and ends at index 2 is "aaa".
The letter 'a' in the substring appears exactly 3 times.
The substring that starts at index 3 and ends at index 8 is "bcbbcc".
The letters 'b' and 'c' in the substring appear exactly 3 times.
The substring that starts at index 0 and ends at index 8 is "aaabcbbcc".
The letters 'a', 'b', and 'c' in the substring appear exactly 3 times.
Example 2:
Input: s = "abcd", count = 2
Output: 0
Explanation:
The number of times each letter appears in s is less than count.
Therefore, no substrings in s are equal count substrings, so return 0.
Example 3:
Input: s = "a", count = 5
Output: 0
Explanation:
The number of times each letter appears in s is less than count.
Therefore, no substrings in s are equal count substrings, so return 0
Return the number of equal count substrings in s.
A substring is a contiguous non-empty sequence of characters within a string.
Example 1:
Input: s = "aaabcbbcc", count = 3
Output: 3
Explanation:
The substring that starts at index 0 and ends at index 2 is "aaa".
The letter 'a' in the substring appears exactly 3 times.
The substring that starts at index 3 and ends at index 8 is "bcbbcc".
The letters 'b' and 'c' in the substring appear exactly 3 times.
The substring that starts at index 0 and ends at index 8 is "aaabcbbcc".
The letters 'a', 'b', and 'c' in the substring appear exactly 3 times.
Example 2:
Input: s = "abcd", count = 2
Output: 0
Explanation:
The number of times each letter appears in s is less than count.
Therefore, no substrings in s are equal count substrings, so return 0.
Example 3:
Input: s = "a", count = 5
Output: 0
Explanation:
The number of times each letter appears in s is less than count.
Therefore, no substrings in s are equal count substrings, so return 0
Forwarded from Leetcode with dani
You are given a sorted array nums of size n and an integer target.
Your task is to find the pair of numbers in the array whose sum is less than or equal to the target and has the largest possible sum.
Return the maximum sum of such a pair. If no valid pair exists, return -1.
Example 1:
Input: nums = [2, 3, 5, 8, 13], target = 10
Output: 10
l
[2, 3, 5, 8, 13],
r
[7,8 , 10]
Explanation: The pair (2, 8) has a sum of 10, which is the largest possible sum less than or equal to 10.
Example 2:
Input: nums = [1, 1, 1, 1], target = 1
Output: -1
Explanation: No pair has a sum less than or equal to 1.
Constraints:
1<=n<=10⁵
Nums is sorted in non-decreasing order.
def targetSum(nums , target):
left = 0
max_ = -1
right = len(nums)-1
while left < right:
sum = nums[left] + nums[right]
if sum == target:
return sum
elif sum > target:
right -=1
elif sum < target:
left += 1
max_ = max(max_,sum)
return max_
Forwarded from Leetcode with dani
"""
Given a binary array nums, return the maximum number of consecutive 1's in the array.
Example 1:
Input: nums = [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
Example 2:
Input: nums = [1,0,1,1,0,1]
Output: 2
Constraints:
1 <= nums.length <= 105
nums[i] is either 0 or 1.
"""
Given a binary array nums, return the maximum number of consecutive 1's in the array.
Example 1:
Input: nums = [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
Example 2:
Input: nums = [1,0,1,1,0,1]
Output: 2
Constraints:
1 <= nums.length <= 105
nums[i] is either 0 or 1.
"""
Forwarded from Maki Asrat
The is the interview question I just had:
Given a binary array nums, return the maximum number of consecutive 1's in the array if you can flip at most one 0.
Example 1:
Input: nums = [1,0,1,1,0]
Output: 4
Explanation:
- If we flip the first zero, nums becomes [1,1,1,1,0] and we have 4 consecutive ones.
- If we flip the second zero, nums becomes [1,0,1,1,1] and we have 3 consecutive ones.
The max number of consecutive ones is 4.
max_cont= 4
max_count= 3
max_count =4
[1,0,1,1,0]
Example 2:
Input: nums = [1,0,1,1,0,1]
Output: 4
Explanation:
- If we flip the first zero, nums becomes [1,1,1,1,0,1] and we have 4 consecutive ones.
- If we flip the second zero, nums becomes [1,0,1,1,1,1] and we have 4 consecutive ones.
The max number of consecutive ones is 4.
Constraints:
1 <= nums.length <= 105
nums[i] is either 0 or 1.
Given a binary array nums, return the maximum number of consecutive 1's in the array if you can flip at most one 0.
Example 1:
Input: nums = [1,0,1,1,0]
Output: 4
Explanation:
- If we flip the first zero, nums becomes [1,1,1,1,0] and we have 4 consecutive ones.
- If we flip the second zero, nums becomes [1,0,1,1,1] and we have 3 consecutive ones.
The max number of consecutive ones is 4.
max_cont= 4
max_count= 3
max_count =4
[1,0,1,1,0]
Example 2:
Input: nums = [1,0,1,1,0,1]
Output: 4
Explanation:
- If we flip the first zero, nums becomes [1,1,1,1,0,1] and we have 4 consecutive ones.
- If we flip the second zero, nums becomes [1,0,1,1,1,1] and we have 4 consecutive ones.
The max number of consecutive ones is 4.
Constraints:
1 <= nums.length <= 105
nums[i] is either 0 or 1.
❤7
Forwarded from ALX Ethiopia
🚨 Only 1 Day Left to Register!
Compete on Codeforces in Ethiopia’s National Competitive Programming Challenge!
💰 PRIZE POOL: 🥇 20,000 | 🥈 15,000 | 🥉 10,000 ETB 🏅 4th: 5,000 | 5th: 3,000 | Top 15: 1,000 Each
Note: All applications will be reviewed and only qualified candidates will receive an Official Acceptance Email to participate.
🗓 ቅዳሜ, ኅዳር 27 2018 (Dec 6, 2025)
⏰ 3፡00 – 11፡00 ሰአት (9 AM – 5 PM)
📍 CapStone ALX Tech Hub, Lideta
🔗 Register: https://luma.com/9pobz8sd
⚠️ Each team member must register individually.
#ALXEthiopia #CodeLeagueEthiopia #CompetitiveProgramming #Codeforces #DSA #DoHardThings #ALXAfrica
Compete on Codeforces in Ethiopia’s National Competitive Programming Challenge!
💰 PRIZE POOL: 🥇 20,000 | 🥈 15,000 | 🥉 10,000 ETB 🏅 4th: 5,000 | 5th: 3,000 | Top 15: 1,000 Each
Note: All applications will be reviewed and only qualified candidates will receive an Official Acceptance Email to participate.
🗓 ቅዳሜ, ኅዳር 27 2018 (Dec 6, 2025)
⏰ 3፡00 – 11፡00 ሰአት (9 AM – 5 PM)
📍 CapStone ALX Tech Hub, Lideta
🔗 Register: https://luma.com/9pobz8sd
⚠️ Each team member must register individually.
#ALXEthiopia #CodeLeagueEthiopia #CompetitiveProgramming #Codeforces #DSA #DoHardThings #ALXAfrica
You tube recap😂 I posted the good ones
But the 4th ranked music should be first
But the 4th ranked music should be first
❤3😁3❤🔥1
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