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kemejemria jmro python memar mefelgu sewoch ke first message gemrachu mayet techlalachu keza betechemari be mangnawm seat erdata kefelegachu conatct argugn https://news.1rj.ru/str/zprogramming_bot

be slk lemetemaru kesr yalwn tetekemu yelayegnaw kalseralachu

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#code_challenge write a code for a Given a string containing just the characters '(', ')', '{', '}', '[', and ']', determine if the input string is valid. An input string is valid if:
Open brackets must be closed by the same type of brackets.
Open brackets must be closed in the correct order

you can submit your answers via https://news.1rj.ru/str/zprogramming_bot

seletemechegn nw share yarekut

አትጠይቅ (?)

"አትመርምር ፣ አትጠይቅ ፣
ልብህ ቢያስብ እንኳን ፣ ምላስህን ጠብቅ፣
"ዝም በል" የሚሉት ቃል ፦
ተመራምሮ ላየው ፣ ብዙ ያስጠይቃል ።

ሲጀመር ፦
አስተዋይ አዋቂ ፣ ጠያቂ...አዕምሮ፣
ከነፍስ ባህርይ፣ በሥጋ አንጎል ቋጥሮ፣
አምላክ ከፈጠረ
ስለምን ዝም ይበል፣ የተመራመረ ?

ሲቀጥል ፦
ልብ የጠየቀውን ፣ አንደበት አውጥቶ ስላልተናገረ፣
የልብብ ሚያውቅ አምላክ፣ እንዳልተጠየቀ እንዴት ተቆጠረ?

ባጭሩ ፦
የሰነፍ አንደበት ፣ ለመልስ ሲቸግረው፣
መርማሪ አዕምሮን፣ "በአትጠይቅ" አሰረው ።

✍ መላኩ አላምረው

#code_challenge write a code that find the longest common prefix in the Given two strings.

from our group member

def bracket_validator(s):
bracket_stack = []
char_tree = ["{([","})]"]
cor = {"}":"{","]":"[",")":"("}
for i in s:
if i in char_tree[0]:
bracket_stack.append(i)
elif i in char_tree[1]:
bracket_stack.pop() if cor[str(i)] == bracket_stack[-1] else False

return False if bracket_stack else True

kemejemria jmro python memar mefelgu sewoch ke first message gemrachu mayet techlalachu keza betechemari be mangnawm seat erdata kefelegachu conatct argugn https://news.1rj.ru/str/zprogramming_bot

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