Hey everyone,

Big news! This channel is evolving to focus on cracking LeetCode problems and sharpening your coding skills.

While I appreciate your interest in Python, I'm excited to embark on this new journey with you all, tackling LeetCode challenges together.

Why LeetCode?

Boost your coding interview skills: LeetCode problems are widely used by top tech companies, and mastering them will put you ahead of the curve.
Test and improve your problem-solving abilities: LeetCode offers a variety of problems ranging from easy to challenging, ensuring there's something for everyone.
Learn from each other: We can discuss solutions, share different approaches, and help each other overcome obstacles.
Get ready to:

Dive into LeetCode problems (all levels): We'll tackle a variety of challenges, from basic algorithms to more complex data structures.
Collaborate and discuss solutions: Share your thought processes, learn from different approaches, and help each other conquer the problems.
Become a LeetCode master: Together, we'll push ourselves and improve our coding skills to new heights.
Are you ready to join the LeetCode challenge?

Let's make this channel a hub for collaboration and LeetCode problem-solving!

P.S. Feel free to suggest specific LeetCode problems you'd like to tackle in the comments below.

Let's code together! let me know your ideas in the comment section and there is another group i created only for python i will post it below.

#leet_code_Q1 #Array Given a non-empty array of integers nums, every element appears twice except for one. Find that single one.

You must implement a solution with a linear runtime complexity and use only constant extra space.



Example 1:

Input: nums = [2,2,1]
Output: 1
Example 2:

Input: nums = [4,1,2,1,2]
Output: 4
Example 3:

Input: nums = [1]
Output: 1 Each element in the array appears twice except for one element which appears only once.

give your answer in the bot below or in the comment section

no_136 on leetcode.com

Try this question. i am not getting enough answers from you

Hint: try to do it with one of the bitwise operationd

Hint2: try Xor operation

lets submit our code

it's good. we did better from 78 % of submitted code in python by running time

Level Up Problem-Solving: LeetCode trains your brain to break down problems, a skill used by 80% of software engineers according to a [Payscale survey]( Indeed salary survey for Software Engineer).

lets do another Question on Leet code

#leet_code_Q2 #Array #leet_code_169 #Majority_Element Given an array nums of size n, return the majority element.

The majority element is the element that appears more than (n / 2)times. You may assume that the majority element always exists in the array.

Example 1:

Input: nums = [3,2,3]
Output: 3
Example 2:

Input: nums = [2,2,1,1,1,2,2]
Output: 2

Let's tackle the question of finding the number that appears only once in a list.

if you want to figure it out your self, dont see the answer!!!!!!!!!!!!!!!!!!

We could iterate through the list, comparing each element to all others to count occurrences. This approach would work, but it has a time complexity of n^2, exceeding the given constraint of linear time (O(n)).



Since the question guarantees that all other elements appear twice, we can exploit this property. Here's how:



Convert the list to a set. Sets eliminate duplicates, leaving only the unique element.

Calculate the sum of the elements in the original list and the set.

Unique number = Sum of list elements - (2 * Sum of set elements)

This method efficiently finds the unique element in linear time.



There's an even better approach called the XOR method. If you'd like an explanation of how it works, I can provide the code and break it down for you class Solution:

def singleNumber(self, nums: List[int]) -> int:

result = 0

for i in nums:

result^=i

return result