👨💻lesson c++
Topic:Types of error
1.Compiler error: This type of error occurs when the code is not written according to the syntax and rules of the programming language, and the compiler is unable to compile the code.
🅰የዚህ አይነቱ ስህተት የሚከሰተው ኮድ በፕሮግራም አገባብ እና በፕሮግራሚንግ ቋንቋ ህግ መሰረት ሳይፃፍ ሲቀር እና አቀናባሪው ኮዱን ማጠናቀር ሲያቅተው ነው።
🅰Dogoggora qindeessaa: Gosti dogongoraa kun kan uumamu yeroo koodii akkaataa sintaksii fi seera afaan sagantaatiin hin barreeffamnee fi qindeessaan koodii qindeessuu yoo dadhabedha.
-means it's SYNTAX error
SYNTAX ስህተት ነው ማለት ነው።
- jechuun SYNTAX dogoggora jechuudha.
2.Runtime error: This type of error occurs when the code is syntactically correct but produces an error during program execution, such as division by zero or accessing an invalid memory location.
🙇 examples int x;
Cout<<1/x<<endl;
-code have no syntax error but when x is 0 its undefined this means it's run time error.
🅰ይህ አይነቱ ስህተት የሚከሰተው ኮዱ በአገባብ ትክክል ሲሆን ነገር ግን በፕሮግራሙ አፈጻጸም ወቅት ስህተት ሲፈጠር ለምሳሌ በዜሮ መከፋፈል ወይም ልክ ያልሆነ የማስታወሻ ቦታ መድረስ።
🅰Gosti dogongoraa kun kan uumamu yeroo koodii galumsaan sirrii ta'e, garuu dogongorri yeroo raawwii sagantichaa kan akka zeeroodhaan qoodu ykn bakka yaadannoo sirrii hin taane argachuu.
3.Logical error: This type of error occurs when the code runs without any errors, but produces incorrect output due to a flaw in the logic or algorithm used in the program.
🅰ይህ አይነት ስህተት የሚከሰተው ኮዱ ያለ ምንም ስህተት ሲሰራ ነው፡ ነገር ግን በፕሮግራሙ ውስጥ ጥቅም ላይ በሚውለው አመክንዮ ወይም አልጎሪዝም ላይ ባለ ጉድለት ምክንያት የተሳሳተ ውጤት ይፈጥራል።
🅰 Gosti dogongoraa kun kan uumamu yeroo koodii dogongora tokko malee raawwatu, garuu sababa mudaa loojikii ykn algoritmiin saganticha keessatti fayyadame irraa kan ka'e bu'aa sirrii hin taane argamsiisa.
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Topic:Types of error
1.Compiler error: This type of error occurs when the code is not written according to the syntax and rules of the programming language, and the compiler is unable to compile the code.
🅰የዚህ አይነቱ ስህተት የሚከሰተው ኮድ በፕሮግራም አገባብ እና በፕሮግራሚንግ ቋንቋ ህግ መሰረት ሳይፃፍ ሲቀር እና አቀናባሪው ኮዱን ማጠናቀር ሲያቅተው ነው።
🅰Dogoggora qindeessaa: Gosti dogongoraa kun kan uumamu yeroo koodii akkaataa sintaksii fi seera afaan sagantaatiin hin barreeffamnee fi qindeessaan koodii qindeessuu yoo dadhabedha.
-means it's SYNTAX error
SYNTAX ስህተት ነው ማለት ነው።
- jechuun SYNTAX dogoggora jechuudha.
2.Runtime error: This type of error occurs when the code is syntactically correct but produces an error during program execution, such as division by zero or accessing an invalid memory location.
🙇 examples int x;
Cout<<1/x<<endl;
-code have no syntax error but when x is 0 its undefined this means it's run time error.
🅰ይህ አይነቱ ስህተት የሚከሰተው ኮዱ በአገባብ ትክክል ሲሆን ነገር ግን በፕሮግራሙ አፈጻጸም ወቅት ስህተት ሲፈጠር ለምሳሌ በዜሮ መከፋፈል ወይም ልክ ያልሆነ የማስታወሻ ቦታ መድረስ።
🅰Gosti dogongoraa kun kan uumamu yeroo koodii galumsaan sirrii ta'e, garuu dogongorri yeroo raawwii sagantichaa kan akka zeeroodhaan qoodu ykn bakka yaadannoo sirrii hin taane argachuu.
3.Logical error: This type of error occurs when the code runs without any errors, but produces incorrect output due to a flaw in the logic or algorithm used in the program.
🅰ይህ አይነት ስህተት የሚከሰተው ኮዱ ያለ ምንም ስህተት ሲሰራ ነው፡ ነገር ግን በፕሮግራሙ ውስጥ ጥቅም ላይ በሚውለው አመክንዮ ወይም አልጎሪዝም ላይ ባለ ጉድለት ምክንያት የተሳሳተ ውጤት ይፈጥራል።
🅰 Gosti dogongoraa kun kan uumamu yeroo koodii dogongora tokko malee raawwatu, garuu sababa mudaa loojikii ykn algoritmiin saganticha keessatti fayyadame irraa kan ka'e bu'aa sirrii hin taane argamsiisa.
@examanswer1
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FRESHMAN TIPS pinned «👨💻lesson c++ Topic:Types of error 1.Compiler error: This type of error occurs when the code is not written according to the syntax and rules of the programming language, and the compiler is unable to compile the code. 🅰የዚህ አይነቱ ስህተት የሚከሰተው ኮድ በፕሮግራም…»
FRESHMAN TIPS
C++ JIMMA UNIVERSITY QUIZ EXAM OUT 20% @examanswer1
Question no.5
✅Answer
#include<iostream>
using namespace std;
int main(){
int i,j;
for(i=0;i<6;i++){cout<<endl<<"#";
if(i==0) cout<<'' ''<<''*'';
for(j=0;j<i,j++)
cout<<" "<<i<<" "<<"*"<<;
cout<<"\n";
}
return 0;
}
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🧑💻@examanswer1
.
✅Answer
#include<iostream>
using namespace std;
int main(){
int i,j;
for(i=0;i<6;i++){cout<<endl<<"#";
if(i==0) cout<<'' ''<<''*'';
for(j=0;j<i,j++)
cout<<" "<<i<<" "<<"*"<<;
cout<<"\n";
}
return 0;
}
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🧑💻@examanswer1
.
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ተማር !
ከስህተትህ ተማር ፣ ከመንገድህ ተማር ፣ ከድልህም ተማር እያንዳንዱ የህይወት መንገድ የራሱ የሆነ ስጦታ አለው ሁላችንም ገና ከእናታችን ሆድ ስንወጣ ሁሉን ጠንቅቀን አላወቅንም ይልቁንስ በጊዜ ሂደት እያደግን ሄድን እንጂ
በየቀኑ አዲስ ነገርን ለማወቅ ትጋ!
ቆንጆ ቀን ተመኘን 🙏
@examanswer1
የእናንተው ምርጥ ጓደኛ 😊
Credit:@Inspire Ethiopia
ከስህተትህ ተማር ፣ ከመንገድህ ተማር ፣ ከድልህም ተማር እያንዳንዱ የህይወት መንገድ የራሱ የሆነ ስጦታ አለው ሁላችንም ገና ከእናታችን ሆድ ስንወጣ ሁሉን ጠንቅቀን አላወቅንም ይልቁንስ በጊዜ ሂደት እያደግን ሄድን እንጂ
በየቀኑ አዲስ ነገርን ለማወቅ ትጋ!
ቆንጆ ቀን ተመኘን 🙏
@examanswer1
የእናንተው ምርጥ ጓደኛ 😊
Credit:@Inspire Ethiopia
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👨💻Lesson c++
Topic🙇Bitwise operation
🔱Bitwise operation is a type of operation that is performed on individual bits or binary digits of a value
There are several types of bitwise operations, including:
1. AND ( & ): Performs a logical AND operation on each bit of two values.
✨ If both bits are 1, the result is 1. Otherwise, the result is 0.
🙇example 10011 &
10101
=10001
2. OR (|): Performs a logical OR operation on each bit of two values.
✨ If either bit is 1, the result is 1. Otherwise, the result is 0.
🙇example 11000 |
01010
=11010
3. XOR (^): Performs a logical XOR (exclusive OR) operation on each bit of two values.
✨ If the bits are different, the result is 1. Otherwise, the result is 0.
🙇example 0101
0111
=0010
4. NOT (! ): Performs a logical NOT operation on each bit of a value.
✨ It flips each bit from 0 to 1 or from 1 to 0.
🙇example 0101 !
=1010
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If u have any comment and question u can ask✋🙋🙋🙋
@examanswer1
.
Topic🙇Bitwise operation
🔱Bitwise operation is a type of operation that is performed on individual bits or binary digits of a value
There are several types of bitwise operations, including:
1. AND ( & ): Performs a logical AND operation on each bit of two values.
✨ If both bits are 1, the result is 1. Otherwise, the result is 0.
🙇example 10011 &
10101
=10001
2. OR (|): Performs a logical OR operation on each bit of two values.
✨ If either bit is 1, the result is 1. Otherwise, the result is 0.
🙇example 11000 |
01010
=11010
3. XOR (^): Performs a logical XOR (exclusive OR) operation on each bit of two values.
✨ If the bits are different, the result is 1. Otherwise, the result is 0.
🙇example 0101
0111
=0010
4. NOT (! ): Performs a logical NOT operation on each bit of a value.
✨ It flips each bit from 0 to 1 or from 1 to 0.
🙇example 0101 !
=1010
share it for ur friends
If u have any comment and question u can ask✋🙋🙋🙋
@examanswer1
.
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FRESHMAN TIPS
Example a=15 b=10 find 1.a|b 2.a&b 3.a! 4.b! 5.a^b
✅Explanation
Given a=15
b=10
then
First we have to change it in binary format.
#1.a|b
15=1+2+4+8
=1111
10=2+8
0101
a|b=1111 |
0101
=1111
a|b=15
#2. a&b
a=1111
b=0101
a&b=0101=2+8=10
#3.a!
a=1111
a!=0000
a!=0
#4.b!
b=0101
b!=1010=1+4=5
b!=5
5.a^b
a=1111
b=0101
a^b=1010=1+4=5
a^b=5
✨✨✨✨✨✨✨✨
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@examanwser1 🌟
✨✨✨✨✨✨✨✨
Given a=15
b=10
then
First we have to change it in binary format.
#1.a|b
15=1+2+4+8
=1111
10=2+8
0101
a|b=1111 |
0101
=1111
a|b=15
#2. a&b
a=1111
b=0101
a&b=0101=2+8=10
#3.a!
a=1111
a!=0000
a!=0
#4.b!
b=0101
b!=1010=1+4=5
b!=5
5.a^b
a=1111
b=0101
a^b=1010=1+4=5
a^b=5
✨✨✨✨✨✨✨✨
share it for ur friends
@examanwser1 🌟
✨✨✨✨✨✨✨✨
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#For_New_Coming_Students
ሰላም ውድ አዲስ ገቢ ተማሪዎችችን🤩🤩🤩
✅ እንደሚታወቀው ወደ ጅማ ዩኒቨርሲቲ ለመግባት ሁለት ቀናት ብቻ ቀርተዋችኋል ሆኖም የጅማ ዩኒቨርሲቲ የተማሪዎች ህብረት እናንተን ለመቀበል ሙሉ ዝግጅቱን ጨርሷል ፤ በተጨማሪም ወደ ዩኒቨርሲቲ በምትገቡበት ጊዜ ጅማ ከተማ መግቢያው ላይ ኬላ ወይም የመጨረሻው ፍተሻ ላይ በምትደርሱበት ጊዜ ከዩኒቨርሲቲው የተመደቡ መኪናዎች እንዲሁም ባጅ(መለያ) የለበሱ የተማሪ ህብረቶች እናንተን ለመቀበል እዚያ ይገኛሉ ከዚያም ከኬላ በተዘጋጁላችሁ መኪኖች በመነሳት የተፈጥሮ ሳይንስ ተማሪዎች ወደ ተመደባችሁበት ካምፓስ ወይም ወደ JIT የምትገቡ ሲሆን የግቢው በር ላይ ትወርዱና ፍተሻ የምታካሂዱ ይሆናል ከዚያም ከምትገቡበት በር እስከ ዶርማችሁ ድረስ ግቢ ውስጥ ባስ የተዘጋጀላችጁ ስለሆነ ወደ ዶርም ትሄዳላችሁ በመቀጠል ዶርም ገብታችሁ እቃዎቻችሁን ካስቀመጣችሁ በኋላ በተቀባይ ተማሪዎች በመታገዝ Workshop ህንፃ ወደሚባል ቦታ በመሄድ ምዝገባችሁን የምታካሂዱ ይሆናል ይህ በእንዲህ እንዳለ እናንተ ይህን በምታደርጉበት ጊዜ ወላጆቻችሁ ግቢ ውስጥ በሩ አካባቢ የተዘጋጀላቸው የእንግዳ መቀበያ ቦታ ስላለ እዚያ የሚጠብቋችሁ ይሆናል።
ለሁላችሁም ያማረ መንገድ እንዲሆንላችሁ እንመኛለን🙏🙏🙏
✅የጅማ ቴክኖሎጂ ኢንስቲቲውት የተማሪዎች ህብረት!
✅Akkam jirtu kabajamtoota barattoota haaraa akkuma beektan Yuunivarsiitii Jimmaa seenuuf guyyaa lama qofatu hafe waan taheef gamtaan barattootaa yuunivarsiitii Jimmaa isin simachuuf qophii hundaa xumuree jira. Kana malees yeroo yuunivarsiitii seentan seensa Magaalaa Jimmaa irratti buufata sakatta'iinsaatti ykn sakatta'iinsa xumuraa irratti konkolaattonni yuunivarsiitii fi barattoota waldaa barattootaa irraa ramadaman baajii uffachuun achitti isin simachuuf ni argamu.Isin gadi bu'uun sakatta'iinsa gaggeessuu ni dandeessu.
Sana booda balbala seentan irraa gara dormii keessanitti mooraa keessatti konkolaataan isiinif qophaa'ee jira.Achiis gara dormii deemtan .Erga dormii seentanii meeshaa keessan galfatanin booda gargaarsa barattoota simannaatiin bakka gamoo Workshop jedhamu deemtanii galmee keessan xumurtu.
Gidduu kana osoo kana gochaa jirtanuu mooraa keessatti naannoo balbalaatti bakki simannaa maatii keessaniif qophaa’e waan jiruuf achitti isin eegu.
⭐️Hunda keessaniif imala bareedaa hawwina 🙏🙏🙏
✅JIMAA INSTIITIYUUTII TEEKNOOLOOJII WALDAA BARATTOOTA!
source: students Union
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✅ እንደሚታወቀው ወደ ጅማ ዩኒቨርሲቲ ለመግባት ሁለት ቀናት ብቻ ቀርተዋችኋል ሆኖም የጅማ ዩኒቨርሲቲ የተማሪዎች ህብረት እናንተን ለመቀበል ሙሉ ዝግጅቱን ጨርሷል ፤ በተጨማሪም ወደ ዩኒቨርሲቲ በምትገቡበት ጊዜ ጅማ ከተማ መግቢያው ላይ ኬላ ወይም የመጨረሻው ፍተሻ ላይ በምትደርሱበት ጊዜ ከዩኒቨርሲቲው የተመደቡ መኪናዎች እንዲሁም ባጅ(መለያ) የለበሱ የተማሪ ህብረቶች እናንተን ለመቀበል እዚያ ይገኛሉ ከዚያም ከኬላ በተዘጋጁላችሁ መኪኖች በመነሳት የተፈጥሮ ሳይንስ ተማሪዎች ወደ ተመደባችሁበት ካምፓስ ወይም ወደ JIT የምትገቡ ሲሆን የግቢው በር ላይ ትወርዱና ፍተሻ የምታካሂዱ ይሆናል ከዚያም ከምትገቡበት በር እስከ ዶርማችሁ ድረስ ግቢ ውስጥ ባስ የተዘጋጀላችጁ ስለሆነ ወደ ዶርም ትሄዳላችሁ በመቀጠል ዶርም ገብታችሁ እቃዎቻችሁን ካስቀመጣችሁ በኋላ በተቀባይ ተማሪዎች በመታገዝ Workshop ህንፃ ወደሚባል ቦታ በመሄድ ምዝገባችሁን የምታካሂዱ ይሆናል ይህ በእንዲህ እንዳለ እናንተ ይህን በምታደርጉበት ጊዜ ወላጆቻችሁ ግቢ ውስጥ በሩ አካባቢ የተዘጋጀላቸው የእንግዳ መቀበያ ቦታ ስላለ እዚያ የሚጠብቋችሁ ይሆናል።
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✥Applied mathematics one
Derivatives part Question
Let F(x)=f(2(g(x)) f(x)=x^4+x^3+1;0<=x<=3
find F'(3)=?
Hint:
g(x)=inverse of f(x)
.
Derivatives part Question
Let F(x)=f(2(g(x)) f(x)=x^4+x^3+1;0<=x<=3
find F'(3)=?
Hint:
g(x)=inverse of f(x)
.
🔥2
✥Applied
Derivative of inverse csc functions .
Y=csc⁻^1(secx) find dy/dx?
Hint:
csc⁻^1 means inverse of csc
.
Derivative of inverse csc functions .
Y=csc⁻^1(secx) find dy/dx?
Hint:
csc⁻^1 means inverse of csc
.
🤔2
FRESHMAN TIPS
✥Applied mathematics one Derivatives part Question Let F(x)=f(2(g(x)) f(x)=x^4+x^3+1;0<=x<=3 find F'(3)=? Hint: g(x)=inverse of f(x) .
✅Explanation👨🏽💼
Hint:
(f⁻)(x)=g(x)
f(a)=c ,(f⁻)'(c)=1/f'(a)
So, c=3 a=?
f(a)=a^4+a^3+1=3
a^4+a^3-2=0
a=1
f(1)=3
g(3)=(f⁻)(3)=1
g'(3)=(f⁻)'(3)=1/f'(1)=1/7
then,
F'(3)=2f'(2g(3))*(g'(3))
=2f'(2)*(1/7)
=88*1/7
=88/7
.
Hint:
(f⁻)(x)=g(x)
f(a)=c ,(f⁻)'(c)=1/f'(a)
So, c=3 a=?
f(a)=a^4+a^3+1=3
a^4+a^3-2=0
a=1
f(1)=3
g(3)=(f⁻)(3)=1
g'(3)=(f⁻)'(3)=1/f'(1)=1/7
then,
F'(3)=2f'(2g(3))*(g'(3))
=2f'(2)*(1/7)
=88*1/7
=88/7
.
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FRESHMAN TIPS
✥Applied Derivative of inverse csc functions . Y=csc⁻^1(secx) find dy/dx? Hint: csc⁻^1 means inverse of csc .
✅Explanation
Hint:(csc⁻^1)'=
-f'(x) / f(x)sqrt((f(x)^2+1))
=-(secx)'/secx sqrt((secx)^2+1))
=-(-tanx secx) / secx sqrt(sec^2+1)
=tanx secx / secx tanx
=1
Hint:(csc⁻^1)'=
-f'(x) / f(x)sqrt((f(x)^2+1))
=-(secx)'/secx sqrt((secx)^2+1))
=-(-tanx secx) / secx sqrt(sec^2+1)
=tanx secx / secx tanx
=1
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