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FRESHMAN TIPS
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FRESHMAN TIPS
Example a=15 b=10 find 1.a|b 2.a&b 3.a! 4.b! 5.a^b
Explanation

Given a=15
b=10

then
First we have to change it in binary format.
#1.a|b
15=1+2+4+8
=1111

10=2+8
0101
a|b=1111 |
0101
=1111

a|b=15


#2. a&b

a=1111
b=0101
a&b=0101=2+8=10

#3.a!
a=1111
a!=0000

a!=0

#4.b!
b=0101
b!=1010=1+4=5

b!=5

5.a^b

a=1111
b=0101
a^b=1010=1+4=5


a^b=5



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እንደሚታወቀው ወደ ጅማ ዩኒቨርሲቲ ለመግባት ሁለት ቀናት ብቻ ቀርተዋችኋል ሆኖም የጅማ ዩኒቨርሲቲ የተማሪዎች ህብረት እናንተን  ለመቀበል ሙሉ ዝግጅቱን ጨርሷል ፤ በተጨማሪም ወደ ዩኒቨርሲቲ በምትገቡበት ጊዜ ጅማ ከተማ መግቢያው ላይ ኬላ ወይም የመጨረሻው ፍተሻ ላይ በምትደርሱበት ጊዜ ከዩኒቨርሲቲው የተመደቡ መኪናዎች እንዲሁም ባጅ(መለያ) የለበሱ የተማሪ ህብረቶች እናንተን ለመቀበል እዚያ ይገኛሉ ከዚያም ከኬላ በተዘጋጁላችሁ መኪኖች በመነሳት የተፈጥሮ ሳይንስ ተማሪዎች ወደ ተመደባችሁበት ካምፓስ ወይም ወደ JIT የምትገቡ ሲሆን የግቢው በር ላይ ትወርዱና ፍተሻ የምታካሂዱ ይሆናል  ከዚያም ከምትገቡበት በር እስከ ዶርማችሁ ድረስ ግቢ ውስጥ  ባስ የተዘጋጀላችጁ ስለሆነ ወደ ዶርም ትሄዳላችሁ በመቀጠል ዶርም ገብታችሁ እቃዎቻችሁን ካስቀመጣችሁ በኋላ በተቀባይ ተማሪዎች በመታገዝ Workshop ህንፃ ወደሚባል ቦታ በመሄድ ምዝገባችሁን የምታካሂዱ ይሆናል ይህ በእንዲህ እንዳለ እናንተ ይህን በምታደርጉበት ጊዜ  ወላጆቻችሁ ግቢ ውስጥ በሩ አካባቢ የተዘጋጀላቸው የእንግዳ መቀበያ ቦታ ስላለ እዚያ የሚጠብቋችሁ ይሆናል።

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የጅማ ቴክኖሎጂ ኢንስቲቲውት የተማሪዎች ህብረት!

Akkam jirtu kabajamtoota barattoota haaraa akkuma beektan Yuunivarsiitii Jimmaa seenuuf guyyaa lama qofatu hafe waan taheef gamtaan barattootaa yuunivarsiitii Jimmaa isin simachuuf qophii hundaa xumuree jira. Kana malees yeroo yuunivarsiitii seentan seensa Magaalaa Jimmaa irratti buufata sakatta'iinsaatti ykn sakatta'iinsa xumuraa irratti konkolaattonni yuunivarsiitii fi barattoota waldaa barattootaa irraa ramadaman baajii uffachuun achitti  isin simachuuf ni argamu.Isin gadi bu'uun sakatta'iinsa gaggeessuu ni dandeessu.
Sana booda balbala seentan irraa gara dormii keessanitti  mooraa keessatti konkolaataan isiinif  qophaa'ee jira.Achiis gara dormii deemtan .Erga dormii seentanii meeshaa keessan galfatanin   booda gargaarsa barattoota simannaatiin bakka gamoo Workshop jedhamu deemtanii galmee keessan xumurtu.
Gidduu kana osoo kana gochaa jirtanuu mooraa keessatti naannoo balbalaatti bakki simannaa maatii keessaniif qophaa’e waan jiruuf achitti    isin   eegu.

⭐️Hunda keessaniif imala bareedaa hawwina 🙏🙏🙏

JIMAA INSTIITIYUUTII TEEKNOOLOOJII WALDAA BARATTOOTA!


source: students Union

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For new coming students

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✥Applied mathematics one

Derivatives part Question

Let F(x)=f(2(g(x)) f(x)=x^4+x^3+1;0<=x<=3
find F'(3)=?

Hint:
g(x)=inverse of f(x)


.
🔥2
✥Applied

Derivative of inverse csc functions .


Y=csc⁻^1(secx) find dy/dx?

Hint:

csc⁻^1 means inverse of csc




.
🤔2
FRESHMAN TIPS
✥Applied mathematics one Derivatives part Question Let F(x)=f(2(g(x)) f(x)=x^4+x^3+1;0<=x<=3 find F'(3)=? Hint: g(x)=inverse of f(x) .
Explanation👨🏽‍💼

Hint:

(f⁻)(x)=g(x)

f(a)=c ,(f⁻)'(c)=1/f'(a)

So, c=3 a=?
f(a)=a^4+a^3+1=3
a^4+a^3-2=0
a=1

f(1)=3


g(3)=(f⁻)(3)=1
g'(3)=(f⁻)'(3)=1/f'(1)=1/7

then,
F'(3)=2f'(2g(3))*(g'(3))
=2f'(2)*(1/7)
=88*1/7
=88/7


.
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FRESHMAN TIPS
✥Applied Derivative of inverse csc functions . Y=csc⁻^1(secx) find dy/dx? Hint: csc⁻^1 means inverse of csc .
Explanation

Hint:(csc⁻^1)'=
-f'(x) / f(x)sqrt((f(x)^2+1))

=-(secx)'/secx sqrt((secx)^2+1))
=-(-tanx secx) / secx sqrt(sec^2+1)
=tanx secx / secx tanx
=1
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"state is collection of institutions which are established and funded by public"is the view of......
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