write a program that check a given number prime or not?

here is one way to do the above question
n=int(input('number:- '))
if n > 2:
for i in range(2,n):
if n%i==0:
print(n,'is not prime')
break
else:
print(n,'is prime')
break
elif n ==2:
print(n,'is prime')
else:
print(n,'is not prime')

https://news.1rj.ru/str/zethioprograming

write a code that add the square of each digits in a give number
eg:- if the given number is 111 then the out put is 3 if it is 23 the out put is 13.
https://news.1rj.ru/str/zethioprograming

here is the solution for the above problem

def sum_squared(n):
sum=0
while n>0:
no=n%10
sum=sum+no**2
n=n//10
print(sum)

https://news.1rj.ru/str/zethioprograming

n=int(input(' '))
sum_squared(n)

#out put
2
4
6
8
we have four even numbers

#write a code for the above out put
https://news.1rj.ru/str/zethioprograming

use the comment section to give your solution

def even(n):
ctr=0
for i in range (1,n):
if i%2==0:
ctr +=1
print(i)
print(f“we have {ctr} even numbers”)
even(10)

n = int(input('number: '))
total = 0
for i in range(2,n,2):
print(i)
total +=1
print(f'we have {total} even numbers')

write a  program that generate 7 random number in the form of  list from one ab to 9.

from the comments
#in the form of list
import random
def easy():
lis = []
i = 0
while i < 7:
   lis.append(random.randint(1,9))
   i+=1
print(lis)
easy()

write a program that count number of odd number in the given number.
example:- input=3687 .#output=2

n=int(input('number:'))
num=0
if n < 0:
    n=-n
while n > 0:
    no=n%10
    if no % 2 != 0:
        num+=1
    n=n//10
print(num)

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